55 class combinations with 4 subclasses each makes for 220, minus a few Pala-Priest combos that are blocked.
55 class combinations with 4 subclasses each makes for 220, minus a few Pala-Priest combos that are blocked.
That doesn't seem right?
Each class combination has 16 possibilities since both classes have 4 options (default and the 3 subclasses). So then it would be 16x55=880 combinations. Without excluding the blocked combinations.
However, in the video there seemed to be more than 3 subclasses per class, so we can't know the actual number.
Wizard/Cipher is Hierophant and Wizard/Priest is thaumaturge, when the opposite would make much more sense. I hope this is fixed, someone write to Josh or something.
However, in the video there seemed to be more than 3 subclasses per class, so we can't know the actual number.
You can if you read the update!
55 class combinations with 4 subclasses each makes for 220, minus a few Pala-Priest combos that are blocked.
That doesn't seem right?
Each class combination has 16 possibilities since both classes have 4 options (default and the 3 subclasses). So then it would be 16x55=880 combinations. Without excluding the blocked combinations.
If there are 4 subclasses per class (default + 3 options), then there are 44 single-class options. So there are 44 choose 2 = 946 multi-class combinations, then you add the 44 single-class options to get a total 990 total combinations (not counting blocked options). However, in the video there seemed to be more than 3 subclasses per class, so we can't know the actual number.
You can't multiclass two subclasses of the same class with each other. At least I don't think so, even though it showed that you can in the video.
Yes - less abilities and everything is per encounter. Choosing spells is going to be tough. They haven't said much about grimoires yet.You can't multiclass two subclasses of the same class with each other. At least I don't think so, even though it showed that you can in the video.
Yes thats why I mentioned it, it wouldn't make sense.
BTW, something else I noticed. It seems like you would have a fairly limited number of abilities. Looking at the power progression, wizards for example would only get a bit more than 2 spells on average per spell level. In general I would be ok with less active ability, it would be preferable to have fewer but more impactful abilities.
They haven't said much about grimoires yet.
55 class combinations with 4 subclasses each makes for 220, minus a few Pala-Priest combos that are blocked.
That doesn't seem right?
Each class combination has 16 possibilities since both classes have 4 options (default and the 3 subclasses). So then it would be 16x55=880 combinations. Without excluding the blocked combinations.
If there are 4 subclasses per class (default + 3 options), then there are 44 single-class options. So there are 44 choose 2 = 946 multi-class combinations, then you add the 44 single-class options to get a total 990 total combinations (not counting blocked options). However, in the video there seemed to be more than 3 subclasses per class, so we can't know the actual number.
Are you not also including combinations like ranger/ranger in this calculation?
They haven't said much about grimoires yet.
They've said enough. Grimoires are no longer receptacles for "memorized" spells but are instead a source of spells. Spells gained on level-up do not go in a grimoire.
Something that isn't mentioned in the update but appears in the video : wizard specializations come with a special ability each, it's not just barring/empowering schools. The Conjurer can summon a familiar and the Transmaster can shapeshift into an ogre.
55 class combinations with 4 subclasses each makes for 220, minus a few Pala-Priest combos that are blocked.
That doesn't seem right?
Each class combination has 16 possibilities since both classes have 4 options (default and the 3 subclasses). So then it would be 16x55=880 combinations. Without excluding the blocked combinations.
If there are 4 subclasses per class (default + 3 options), then there are 44 single-class options. So there are 44 choose 2 = 946 multi-class combinations, then you add the 44 single-class options to get a total 990 total combinations (not counting blocked options). However, in the video there seemed to be more than 3 subclasses per class, so we can't know the actual number.
Are you not also including combinations like ranger/ranger in this calculation?
Oh yeah, forgot about that. Then I think it should be ((8 * 4 * 46) + (3 * 6 * 44)) / 2 + 50 = 1182. For the 8 classes that have 4 subclasses, you can choose one of 46 other options, and similarly for the 3 classes with 6 subclasses. Divide by 2 because you've counted every option twice, and add the remaining 50 single-classes. Hopefully I haven't fucked up again.